The energy of a photon (E) = "\\dfrac{hc}{\\lambda}"
E = "\\dfrac{6.63\u00d710^{-34}\u00d73\u00d710^8}{532\u00d7 10^{-9}}"
"= 3.74\u00d7 10^{-19}\\ J"
Power output = 25mW = "25 \u00d7 10^{-3}"W.
This means, the energy emitted in one second = "25 \u00d7 10^{-3}"J
Number of photons in one second = "\\dfrac{25\u00d710^{-3}}{3.74\u00d710^{-19}} = 6.68 \u00d7 10^{16}"
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