(a) Ideal Gas Law
pV = nRT
R = 0.082058 L atm/K mol
n = 1.0 mol
V = 3 L
T = 273.15 K
"p = \\frac{nRT}{V}"
"p = \\frac{1 \\times 0.082058 \\times 273.15}{3} = 7.47 \\; atm"
(b) van der Waals equation
"P + \\frac{n^2a}{V^2}(V \u2013 nb) = nRT"
"P = \\frac{nRT}{V \u2013 nb} - \\frac{n^2a}{V^2}"
"a = 3.59 \\;L^2\\;atm\/mol^2"
"b = 0.0427 \\;L\/mol"
"P = \\frac{1 \\times 0.082058 \\times 273.15}{3 \u2013 (1 \\times 0.0427)} - \\frac{1^2 \\times 3.59}{3^2} = 7.579 \u2013 0.399 = 7.18 \\;atm"
Comments
Leave a comment