Question #144054
A sample of 1.000 mol of CO2(g) is confined to a 3.000-L container at 0.000°C. Calculate the pressure of the gas using (a) the ideal-gas equation and (b) the van der Waals equation.
1
Expert's answer
2020-11-22T11:12:00-0500

(a) Ideal Gas Law

pV = nRT

R = 0.082058 L atm/K mol

n = 1.0 mol

V = 3 L

T = 273.15 K

p=nRTVp = \frac{nRT}{V}

p=1×0.082058×273.153=7.47  atmp = \frac{1 \times 0.082058 \times 273.15}{3} = 7.47 \; atm

(b) van der Waals equation

P+n2aV2(Vnb)=nRTP + \frac{n^2a}{V^2}(V – nb) = nRT

P=nRTVnbn2aV2P = \frac{nRT}{V – nb} - \frac{n^2a}{V^2}

a=3.59  L2  atm/mol2a = 3.59 \;L^2\;atm/mol^2

b=0.0427  L/molb = 0.0427 \;L/mol

P=1×0.082058×273.153(1×0.0427)12×3.5932=7.5790.399=7.18  atmP = \frac{1 \times 0.082058 \times 273.15}{3 – (1 \times 0.0427)} - \frac{1^2 \times 3.59}{3^2} = 7.579 – 0.399 = 7.18 \;atm


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