Answer to Question #144043 in General Chemistry for Phoenix

Question

Nitrogen and hydrogen gases react to form ammonia gas as follows:
N₂(g) + 3 H₂(g) = 2 NH₃(g)
At a certain temperature and pressure, 1.2 L of N₂ reacts with 3.6 L of H₂. If all the N₂ and H₂ are consumed, what volume of NH₃, at the same temperature and pressure, will be produced?

Answer 1

calculate the amount of substance N₂ and H₂

n(N₂) = V(N₂)/V_M = 1,2 L / 22,4 L/moll = 0,054 moll

n(H₂) = V(H₂)/V_M = 3,6 L / 22,4 L/moll = 0.16 moll

n(N₂):n(H₂) = 0.054:0.16 = 1:3

volume of NH₃ can be calculated by both volume N₂ or H₂

If by both volume N₂

V(NH₃) = V(N₂) × 2V_M / V_M = 1.2 L × (2×22.4 L/moll) / 22.4 L/moll = 2.4 L

If by both volume H₂

V(NH₃) = V(H₂) × 2V_M / 3V_M = 3.6 L × (2×22.4 L/moll) / (3×22.4 L/moll) = 2.4 L

Volume of NH₃ is 2.4 L