d= 2.5cm
L=5.5m
P=1.78 torr
T=35°c= 308.15K
Volume of cylindrical , V=2πr2LV=2πr²LV=2πr2L
V=2 ×π ×(1.25×10-2)2×5.5
V=9.06m3
PV=nRTPV= nRTPV=nRT
9.06×1.78 = n× 8.314×308.15
n=0.006moles
Imole =20g
Mass=1.2g
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