We can calculate molar concentration of Br2. No Br is present initially.
C(Br2)inic=1.07M
It is given that 1.20 % of the Br2 undergoes dissociation. That is, the amount of Br2 after dissociation is 1001.20(1.07)=0.0128M . The equilibrium concentration of Br2 is (1.07 – 0.0128) = 1.06 M. The concentration change in Br is 2×(0.0128)=0.0256M
Kc=[Br2][Br]2
Kc=1.06(0.0256)2=6.18×10−4
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