Answer to Question #143981 in General Chemistry for Javier

Question

What is the new % (m/v) concentration when water is added to 25.0 mL of 20.0% (m/v) NaOH to make 300.0 mL of a diluted NaOH solution?

Answer 1

We know the formula,

V₁S₁ = V₂S₂

Where, V₁ & S₁ are volume and concentration of solution of NaOH solution before the dilution.

And, V₂ & S₂ are volume and concentration of solution of NaOH solution after the dilution.

Given, V₁ = 25.0 mL, S₁= 20.0%(m/v)

V₂ = 300 mL

So, S₂ = V₁S₁/V₂

= (25×20/300) %(m/v)

= 1.667 %(m/v)

So,

The new concentration = 1.667 % (m/v)