Answer to Question #143875 in General Chemistry for Abigail Cruz

Question

What volume of of O2 would be required to react with excess SO2 at STP to produce 0.5 mole of SO3 by the reaction
SO2 + O2 ---> SO3

Answer 1

2SO₂ + O₂ → 2SO₃

n(O₂) = $\frac{1}{2}$ n(SO₃) = 0.25 mol

1 mol of any gas occupies 22.4 L of volume at STP.

V(SO₂) =$0.25\; mol \times 22.4 \;mol/L = 5.6\; L$