CaO + 3C → CaC2 + CO
m(C) = 10.2 g
n = m/M
"n(C) = \\frac{10.2}{12} = 0.85 \\;mol"
"n(CaC_2) = \\frac{1}{3}n(C)"
"n(CaC_2) = \\frac{1}{3} \\times 0.85 = 0.283 \\;mol"
M(CaC2) = 40 + 24 = 64 g/mol
"m(CaC_2) = 0.283 \\times 64 = 18.11 \\;g"
Answer: 18.11 g
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