a) Equllibrium concentration= N2H4(x)×N2H5+OH−(x)
Equation for equilibrium constant
= N2H4[N2H6+][OH−]
Substituting values in the equation yields;
0.01−xx×x =8.9×10−16
=x2+(8.9×10−16×0.01M)21
Using the quadratic formula;
a=1b=8.6×10−7c=−8.9×10−16
−b−+ 2ab2−4ac
=−8.6×10−7−+ 2(1)(8.6×10−7)2−4(1)(8.9×10−16
=−1.699×10−6M
b) pH=−logKb×Co
=−log(Kb×Co)21
=−log(8.9×10−16×0.01M)21
=−log2.983×10−9
pH=8.5
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