Question

How many grams are needed to make a 6.5 mol/L solution of calcium chloride in 500 ml flask

Answer 1

Solution:

$\nu(CaCl_2)=V\times C_M=0.5 L\times 6.5 \frac{mol}{L}=3.25\,mol$

$m(CaCl_2)=\nu\times M=3.25\,mol\times111.08\, \frac{g}{mol}=361.01 \,g$

Answer: 361.01 g