Question #143397
Number of ions present in 4.25 moles of fe
1
Expert's answer
2020-11-09T14:11:53-0500

A mole of Fe atoms contains 6.02×1023 Fe atoms.

4.25 moles of Fe atoms contains 4.25×6.02×1023=2.55×10244.25 \times 6.02 \times 10^{23} = 2.55 \times 10^{24} atoms


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