Answer to Question #143099 in General Chemistry for Jairus

Question

How many molecules are there in 985ml if nitrogen at 0.0°C and 1.00x10⁶mm Hg

Answer 1

V (N₂)= 985 ml = 985x10^-6 m³

T = 0.0°C = 273,2 K

p =  1,00x10⁶mm Hg = 133,32x10⁶ Pa

pV = nRT

R = 8.314 J⋅K⁻¹⋅mol⁻¹

n = pV/(RT)

n(N₂) = (133,32x10⁶ x 985x10^-6) / (8,314*273,2)= 57,815 moles

n = N/N_A

N = n x N_A

N(N₂) = 57,815 x 6.02x10²³ = 3.48x10²⁵