Answer to Question #143046 in General Chemistry for nalani

Question

how many grams of water can be formed when 80 grams of sodium hydroxide reacts with an excess of sulfuric acid in solution?

Answer 1

H2SO4 + 2NaOH --> Na2SO4 +2 H2O

is the balanced equation

mols of NaOH present = 80 g/40 g/mol = 2 mols

According to balanced equation 2 mol NaOH yield 2 mol water

Mass of water formed = 2 mol water * 18.015 g/mol = 36.03 g

Answer

mass of water formed = 36.0 g