Answer to Question #143004 in General Chemistry for Matthew Lattimore

General Chemistry

Question #143004

How many Ca3(PO4)2 molecules are in 7.54 g of calcium phosphate?

Expert's answer

M(Ca₃(PO₄)₂) = 310.18 g/mol

"n = \\frac{m}{M}"

"n = \\frac{7.54}{310.18} = 0.024 \\;mol"

Answer: 0.024 mol

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