Question

How many Ca3(PO4)2 molecules are in 7.54 g of calcium phosphate?

Answer 1

M(Ca₃(PO₄)₂) = 310.18 g/mol

$n = \frac{m}{M}$

$n = \frac{7.54}{310.18} = 0.024 \;mol$

Answer: 0.024 mol