Answer to Question #142977 in General Chemistry for Shay

Question

Consider the following reaction that was run at STP, if 200 mL of nitrogen are reacted with 150 mL of oxygen what is the maximum number of grams of NO2 that could be produced?
N2+2O2–>2NO2

Answer 1

N₂ + 2 O₂ = 2 NO₂

Quantity of N₂: 0.200 L / (22.4 L/mol) = 0.0089 mol

Quantity of O₂: 0.150 L / (22.4 L/mol) = 0.0067 mol

According to the reaction, nitrogen is in excess.

The quantity of NO₂ is equal to the quantity of oxygen: 0.0067 mol

The mass of NO₂: 0.0067 mol * (46 g/mol) = 0.3 g

Answer: 0.3 g