Answer to Question #142892 in General Chemistry for Tej R Ekkurthi

Question

What volume of 17.8 M sulphuric acid solution would be needed to make 2.00 L of 0.200 M solution by dilution of the original, concentrated stock solution?

Answer 1

Proportion 1:

0.2 mol – 1 L

x mol – 2 L

x = 0.4 mol is needed to make the new solutions

Proportion 2:

17.8 mol – 1 L

0.4 mol – y

y = 0.0225 L = 22.5 mL - needed volume of 17.8 M sulphuric acid solution

Answer: 22.5 ml