Answer to Question #142610 in General Chemistry for daria

Question

What is the percent mass of oxygen in 87 g of hydrogen peroxide

Answer 1

Solution:

Molar mass of H₂O₂ = 34.01 g/mol

Mass of O in 1 mol H₂O₂ = 2×16 = 32 g

%O = 32g O / 34.01g H₂O₂ × 100% = 94.09 %

Mass O = 32g O / 34.01g H₂O₂ × 87g H₂O₂ = 81.86 g

Answer: the percent mass of oxygen is 94.09% or 81.86 grams of O.