What is the pressure of 1.75 moles of a gas that occupies 35 L at -50 ˚C?
Q142580
What is the pressure of 1.75 moles of a gas that occupies 35 L at -50 ˚C?
Solution:
In question, we are given,
moles of gas, n = 1.75moles
The Volume occupied by gas, V = 35L
Temperature of gas, T = -500C.
Gas constant, R = 0.08206 L-atm/mol-K
We can use this information in the ideal gas formula, PV = nRT, and find the Pressure of the gas.
In the ideal gas equation, we must use Temperature in kelvin.
Convert -500C to Kelvin by using the formula,
"T (K) = T(^0C ) + 273.15"
T(K) = -50 + 273.15 = 223.15K
Substitute all the given information in the ideal gas equation, we have
P * 35L = 1.75mol * 0.08206 L-atm/mol-K * 223.15K ;
P * 35L = 32.045 L-atm
divide both the side by 35L we have
P*35L/35L = 32.045 L-atm/35L
P = 0.9156 atm ;
In question, the quantity with the least number of significant figures is 35L. It is in 2 significant figures.
So our final answer must also be in 2 significant figures.
0.9156 atm in 2 significant figures can be written as 0.92 atm.
Hence, the pressure of the gas is 0.92 atm.
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