5 % w/V iron (II) sulfate solution means
100 ml solution have 5 g of iron(II) sulfate
1 ml solution have = 5/100 g of iron(II) sulfate
75 ml solution have = (5/100)×75 g of iron(II) sulfate
=3.75 g iron(II) sulfate
Hence, 3.75 g of iron (II) sulfate is found in 75mL of 5%w/V solution
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