Answer to Question #142210 in General Chemistry for emely

Question

According to the reaction C2H6O(g) + O2(g) = CO2(g) + H2O(g). 31.7 grams of C2H6O reacts eith 23.5 grams of oxygen to produce ____ grams of water vapor. What is yhr percent yield of the rreaction if 30.0 grams of carbon dioxide were actually made?

Answer 1

Balanced equation : C₂H₆O +3O₂ = 2CO₂ +3H₂O

The limiting reagent in this reaction is O₂

3O₂ =3H₂O

[3×16×2g] O2 = (3×18)g H20

1g O₂= (3×18)/(3×32)g H20

23.5g O₂= (3×18)/(3×32)×23.5g H20

23.5g O₂ will produce 13.22g of H₂O

3O₂= 2CO₂

3×32g O₂= 2× 44g CO₂

1g O₂= (2× 44)/(3×32)g CO₂

23.5g O₂= (2× 44)/(3×32)× 23.5g CO₂

23.5g O₂ will produce 21.54g CO₂

% yield =[actual yield / theoretical yield] ×100%

%yield = [30/21.54] ×100% = 139.28%

Usually the actual yield < theoretical yield.

So, there seem to be an error in the data provided