Answer to Question #141677 in General Chemistry for sarah

General Chemistry

Question #141677

what is the solubility of CaF2 (Ksp = 1.46x10^-10) in a solution that has [F-] = 1.21M?

Expert's answer

Ksp=[Ca²⁺] * [F^-]²

[Ca²⁺]=Ksp/[F^-]²=1.46x10^(-10)/1.21²=9.97*10^-11;

S=∛(Ksp/4)= 2.92 * 10^-4

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