m (KF) = 116 g
n (KF) = m (KF)/M (KF) = 116 / (39 + 19) = 58 / 116 = 0.5 mol
C (KF) = n (KF) / V(solution) = 0.5 mol / 4 L = 0.125 mol/L
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment