Answer to Question #141354 in General Chemistry for yara

Question #141354

What is the concentration, in ppm, if 0.808 grams of CaCl2 is dissolved in 250.0 ml of water.

Expert's answer

0.808 g x 1000 = 808 mg.

250 ml/1000 = 0.25 L.

808 mg/0.25 L= 3232 mg/L = ppm.

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