We know that: 6 ppm = 6 mg/l
6 mg/l = 0.050/x
Volume of solute (x) = 0.050/6 = 0.008 l
Assuming density of solute is 1 g/ml = 1 kg/l,
actual mass of the solute is:
m (solute) = 0.008 kg = 8 g = 8000 mg
mass of solution = mass of solute + mass of solvent = 0.050 mg + 8000 = 8000.05 mg
Comments
Leave a comment