Q141268
There are three naturally occurring isotopes of the hypothetical element hilarium 40Hi,
41Hi, and 43Hi. The percentages of these isotopes are the following:
Hilarium Isotopes Natural Abundance in %
40 Hi 29.4%
41 Hi 37.3%
43Hi 33.3%
You can assume that the atomic masses are exactly equal to the mass number. Calculate
the weight of “naturally” occurring hilarium and report it as you would for any other naturally occurring element.
Solution :
We can use the formula of Average atomic mass for finding atomic mass of Hilarium.
Average atomic mass = Σ (mass # of Isotope * natural abundance ) / 100
Average atomic mass = ( 40 * 29.4 + 41 * 37.3+ 43 * 0.333) / 100
= (1176 + 1529.3 + 1431.9)/100
= 41372/100
= 41.372 amu
in 3 significant figure the answer is 41.4 amu or 41.4 g/mol .
Please also refer to the images I have attached with this for more explanation.
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