Answer to Question #141256 in General Chemistry for Hayden Pesina

Question

If 50.9 g of aspirin (C₉H₈O₄) are produced from 79.8 g of C₇H₆O₃, what is the percent yield from the reaction below?
C₇H₆O₃ (s) + C₄H₆O₃ (s) → C₉H₈O₄ (s) + HC₂H₃O₂ (aq).

Answer 1

M(C₉H₈O₄) = 180.15 g/mol

M(C₇H₆O₃) = 138.12 g/mol

$n(C₇H₆O₃) = \frac{79.8}{138.12} = 0.577 \;mol$

$n(C₇H₆O₃) = n(C₉H₈O₄) = 0.577 \;mol$

$m(C₉H₈O₄) = 0.577 \times 180.15 = 103.94 \;g$

Proportion:

103.94 – 100 %

50.9 – x

$x = \frac{50.9 \times 100}{103.94} = 48.97$ % (the percent yield from the reaction)

Answer: 48.97 %.