Answer to Question #141100 in General Chemistry for Dm

Question

If all of the chloride in a 3.734 g sample of an unknown metal chloride is precipitated as agcl with 70.90 ml of 0.2010 m agno3 what is the percentage of chloride in the sample

Answer 1

Solution:

0.2010 molar AgNO₃ solution means

1000 ml of solution contain 0.2010 mole of AgNO₃

1 ml of solution contain (0.2010/1000) mole AgNO₃

70.90 ml of solution contain

= 70.90×(0.2010/1000) mole AgNO₃

= 14.251×10^-3 mole AgNO₃

AgNO₃ react with Cl^– according to the following equation:

AgNO₃ + Cl^– ————> AgCl + NO₃^–

1mole of AgNO₃ is required to fully reacts with 1 mole of Cl^–

So,

If 14.251×10^-3 mole AgNO₃ react then there must be 14.251×10^-3 mole Cl^– in the given 3.734 g of unknown metal chloride

molar mass of Cl^– is = 35.5 g

14.251×10^–3 mole Cl^– has mass

=(35.5×14.251×10^-3) g

= 0.506 g

So, percent of chloride in 3.734 g of metal chloride

= (0.506 g/3.734 g)×100 %

= 13.548 %

Hence, 13.548 % of chloride present in 3.734 g of unknown metal chloride