Answer to Question #140960 in General Chemistry for Stephanie Reyes

Question

How many moles of CO2 are produced when 7.0 mol of C3H8 are burned in excess of oxygen in a gas grill?

Answer 1

Given that 7.0 mol of C₃H₈burns in excess Oxygen to produce CO₂ and water, the equation will be as follows:

C₃H₈+ 5O₂ = 3CO₂ + 4H₂O

Mol ratio of C₃H₈ to CO₂ is 1:3, therefore;

Moles of C₂2 = 3.0mol(CO₂)× 7.0mol(C₃H₈)/1.0mol(C₃H₈)

Moles of CO₂ produced = 21.0 moles