Answer to Question #140789 in General Chemistry for Marcus

Question

250 g of 50% HNO₃ were diluted with 150 g of water. Calculate the mass percentage of diluted acid.

How do I solve this? Step 1 to finish please.

Answer 1

$250g$ initial solution contains $50\% \,\, HNO_3$

$\therefore$ mass of $HNO_3$ = $= 50\% \times 250g = \dfrac{50}{100} \times 250g = 125g$

Mass of final solution = $250g$ of $50\% \, HNO_3$ solution + $150g$ of Water = $450g$

Mass percentage of the acid =

$\dfrac{mass \ of \ acid}{mass \ of \ final \ solution} \times 100\%$

$= \dfrac{125}{400} \times 100\%$

$= 31.25 \%$