1. Kb=a^2xC
a=✓(Kb/C)=✓(2.7x10-6/1.38)= 0,00139875721. = 0.1398 %
2. [H+]=antipH=3.16227766017E-05
a=3.16227766017E-05/0.158 = 0,000200144156
Kb=a^2xC = 0,000200144156^2 x 0.158 = 6,32911395e-9.
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