H2S=2H+SH_2S = 2H + SH2S=2H+S
This means,
1 mole of H2SH_2SH2S contains 1 mole of Sulfur atoms.
∴\therefore∴ 0.400 moles of H2SH_2SH2S contains 0.4000.4000.400 moles of Sulfur atoms.
1 mole of Sulfur atoms = 32g
0.400 moles of Sulfur atoms = x
x =0.400×321= \dfrac{0.400 \times 32}{1}=10.400×32 g
x =12.8= 12.8=12.8g
∴ 12.8\therefore \ 12.8∴ 12.8g of Sulfur is in 0.400 mol of H2SH_2SH2S
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