Answer to Question #140507 in General Chemistry for Ashley

Question #140507
A solution contains 0.428 M sodium fluoride and 0.284 M hydrofluoric acid.

Calculate the pH of this solution. The Ka of HF is 7.20×10-4.

pH =
1
Expert's answer
2020-11-02T08:44:04-0500

HF - weak acid ;

NaF - its conjugate base;


The Henderson–Hasselbalch equation:

pH = pKa + lg([F-]/[HF]);

pKa=-lg(Ka);

pH=-lg(7.2*10-4) + lg(0.428/0.284) =3.3


Answer: pH=3.3


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