Answer to Question #140297 in General Chemistry for George

Question

Butane gas, C4H10, is combusted to produce carbon dioxide and water vapour. If 0.67 mol of butane are reacted, how many moles of water vapour are produced?

Answer 1

2C₄ H₁₀ + 13 O₂ = 8 CO₂ +10 H₂O

n (C4 H10 )= 0,67 mole  
n (H2O)=10*0.67/2=3,35 mole

answer: 3,35 mole