Solution:
"\\nu(H)=4\\times\\nu(C_4H_4S_2)=4\\times4.15\\times10^{-23}\\,mol=16.6\\times10^{-23}\\,mol"
"N(H)=\\nu(H)\\times N_A=16.6\\times10^{-23}\\,mol\\,\\,\\times6.02\\times10^{23}{mol^{-1}}\\approx100"
Answer:
100 atoms
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