2H2+O2=2H2O
At first, the limiting reagent should be found.
n=m/M,
n(H2)=2/2=1(mol),
n(O2)=16/32=0.5(mol).
According to the chemical equation, the ratio of moles of H2:O2 should be 2:1 (or 1:0.5), the same as it is given. So, all the reagents are consumed.
m(H2O)=2+16=18(g).
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