Answer to Question #140158 in General Chemistry for Javier

Question

A 2.50 liter sample of helium gas has a pressure of 500. mm Hg. What will the new pressure be in mm Hg if the volume is reduced to 1.00 liter?

Answer 1

According to Boyle's law,

$P_1V_1=P_2V_2$.

Therefore,

$P_2=\frac{P_1V_1}{V_2}=\frac{500.mmHg\times2.50L}{1.00L}=1250mmHg$

Answer: 1250 mmHg