According to Boyle's law,
P1V1=P2V2P_1V_1=P_2V_2P1V1=P2V2.
Therefore,
P2=P1V1V2=500.mmHg×2.50L1.00L=1250mmHgP_2=\frac{P_1V_1}{V_2}=\frac{500.mmHg\times2.50L}{1.00L}=1250mmHgP2=V2P1V1=1.00L500.mmHg×2.50L=1250mmHg
Answer: 1250 mmHg
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