Question #140158
A 2.50 liter sample of helium gas has a pressure of 500. mm Hg. What will the new pressure be in mm Hg if the volume is reduced to 1.00 liter?
1
Expert's answer
2020-10-28T08:40:30-0400

According to Boyle's law,

P1V1=P2V2P_1V_1=P_2V_2.

Therefore,

P2=P1V1V2=500.mmHg×2.50L1.00L=1250mmHgP_2=\frac{P_1V_1}{V_2}=\frac{500.mmHg\times2.50L}{1.00L}=1250mmHg


Answer: 1250 mmHg


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