Answer to Question #140151 in General Chemistry for Javier

Question

When 2.00 liters of SO3 gas at STP react, how many grams of O2 gas will form?
2SO3(g) → 2SO2(g) + O2(g)

Answer 1

At STP volume of 1 mole of any gas = 22.4 L

At STP volume of 1mole of SO₃ =22.4 L

So,

at STP volume of 2mole of SO₃ =44.8 L

According to about chemical equation

From 2 mole of SO₃ gas 1 mole of O₂ form

So,

from 44.8 L of SO₃ gas 32 g O₂ is form

From 1 L of SO₃ gas (32/44.8) g O₂ is form

From 2 L of SO₃ gas [(32/44.8)×2] g O₂

= 1.429 g O₂

Hence,

When 2.00 liters of SO₃ gas at STP react 1.429 g O₂ will produce.