Answer to Question #140147 in General Chemistry for ola

Question

Gaseous butane CH3CH22CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O

. Suppose 11.6 g of butane is mixed with 10. g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.

Answer 1

0.3125mol            Xmol

2C₄H₁₀ + 13O₂ = 8CO₂ + 10H₂O

            13mol               10mol

n(C₄H₁₀) = m(C₄H₁₀)/M(C₄H₁₀) = 11.6g/58g/mol = 0.2 mol (excess).

n(O₂) = m(O₂)/M(O₂) = 10g/32g/mol = 0.3125mol (deficiency).

n(H₂O) = X = (0.3125 × 10 / 13) mol = 0.2403mol.

m(H₂O) = n(H₂O) × M(H₂O) = 0.2403 mol × 18 g/mol = 4.3254g ≈ 4.33g.