"CP_{450} = 1.435 + 2.19 \\times 10^{-3} \\times 450 = 2.4205 \\;kJ\/kg\\;K"
"CP_{550} = 1.435 + 2.19 \\times 10^{-3} \\times 550 = 2.6395 \\;kJ\/kg\\;K"
"\u2206CP = 2.6395 \u2013 2.4205 = 0.219 \\;kJ\/kg\\;K"
The heat capacity was changed by 0.219 units, so we need to supply 0.219 kJ of heat to the heater per kg of the liquid heated.
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