Answer to Question #140034 in General Chemistry for ari

Question

What is the de Broglie wavelength, in centimeters, of a 12.4 g hummingbird flying at 40 mph

Answer 1

We can list down the data available in the question, changing all values to appropriate SI units:

• h=6.626×10^-34Js

• m=12.4×10^-3kg

v=1.20×102mph×0.447m/s/mph=53.64m/s

Now, the de Broglie wavelength is:

λ=(6.626×10^-34J.s)/(12.4×10^-3kg) ×(53.64m/s)=9.96×10^-34m

We can change this to centimeters by multiplying by 100:

λ=9.96×10^-32cm