Question #139990
Octane (C3H18) is a major component of gasoline. When octane burns in excess oxygen water is produced as well as carbon dioxide. The density of gasoline is 0.79gmL-1. What volume of carbon dioxide(at STP) is produced from the combustion of 1.0L of octane.
1
Expert's answer
2020-10-23T09:15:54-0400

The equation of the given reaction is

2C8H18 + 25O2 --> 16CO2 + 18H2O


The mass of octane equals 0.79g/mL×1000mL=790g0.79g/mL\times1000mL=790g


n(CO2)=790g(C8H18)114.2g/mol×16mol(CO2)2mol(C8H18)=55.3moln (CO_2)=\frac{790g (C_8H_{18})}{114.2g/mol}\times\frac{16mol(CO_2)}{2mol(C_8H_{18})}=55.3mol


V(CO2)=55.3mol×22.4L/mol=1.24103LV(CO_2)=55.3mol\times22.4L/mol=1.24\cdot10^3L


Answer: 1.24103L1.24\cdot10^3L


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