Question #139890
How much heat is released by a system when 45 J of work is done on it to decrease its energy to 23 J
1
Expert's answer
2020-10-23T09:15:00-0400

To solve the problem, the use of the first law of thermodynamic is required:

ΔU=ΔQΔW\Delta U = \Delta Q - \Delta W

where ΔU\Delta U is a change in internal energy of a system, ΔQ\Delta Q is a heat put into the system and ΔW\Delta W is a work done by or on the system on its surroundings.

To find the amount of heat released by the system the equation have to be re-written in a following form:

ΔQ=ΔU+ΔW\Delta Q = \Delta U + \Delta W

Since the work was done by the system, the ΔW\Delta W has a negative sign and equals to -45J.


The heat released then equals to:

ΔQ=23J45J=22J\Delta Q = 23J - 45J = -22J




Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS