Answer to Question #139798 in General Chemistry for Emmanuela

Question

There are two possible methods for recovering copper from a solution of copper (II) sulfate, one uses precipitation and the other uses redox.
Copper(II) ions can be precipitated as copper(II) carbonate.
CuSO4(aq) + Na2CO3(aq) → CuCO3(s) + Na2SO4(aq)

How many mL of 0.742 M Na2CO3 would be needed to precipitate all of the copper ions in 40.2 mL of 0.640 M CuSO4?

Answer 1

N(Cuso4)=cv

0.640x40.2=25.728mol/1000

0.0257mol

V(Na2Co3)= N/c

0.0257/0.742=0.0346L or 34.6mL