Answer to Question #139771 in General Chemistry for Destiny

Question

How many moles of NaOH are present in 26.5 ml of 0.290 M NaOH

Answer 1

Given,

Volume of NaOH solution,

V_NaOH = 26.5 ml

Concentration of NaOH solution,

S_NaOH = 0.290 M

It means that ,

In 1 liter = 1000 ml of solution 0.290 mole of NaOH are present

So, in 1 ml of solution 0.290 Mole of NaOH will be present

In 26.5 ml solution

[ (0.290/1000)×26.5 ] mole of NaOH will present

= 7.685 × 10^-3 mole NaOH

Hence, 7.685 × 10^-3 moles of NaOH are present in 26.5 ml of 0.290 M NaOH