Answer to Question #139761 in General Chemistry for Javier

General Chemistry

Question #139761

What volume of hydrogen at STP is released when 8.35 g Mg reacts? (Assume that the amount of HCl is enough for the reaction.)

Expert's answer

Mg+2HCl=MgCl₂+H₂

n(H₂)=n(Mg)=8.35/24.3=0.344 mol

V(H₂) = 0.334*22.4 = 7.70 l

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