Question

The solubility of potassium nitrate is at 20°C is 250g/L. How many grams of potassium nitrate is needed to be dissolved in 150mL of water?

Answer 1

Proportion:

250 g – 1000 mL

x – 150 mL

$x = \frac{250 \times 150}{1000} = 37.5 \;g$

Answer: 37.5 g