Answer to Question #139663 in General Chemistry for Suryansh Chaudhary

Question

What is the ksp expression for PBI2 when 1.5 M Cal2 is added?

Answer 1

the ksp expression for PBI2 

PbI₂$\iff$ Pb²⁺ + 2I^-

x 2x

K_sp= [Pb]²⁺ [I^-]²

Value of Ksp is 1.4 × 10^-8

1.4×10^-8= 4x³

X³=3.5×10^-9

X= 1.1518×10^-3

So the concentration of I^- is

3.036×10^-3

Let the PbI2 added in 1.5 M NaI

[Pb²⁺] = sM

[I^-] = (2s + 1.5)M

K_sp for PbI₂ is

K_sp= [sM] [2s+1.5]M