The equation for this reaction is
2NaOH + H2SO4 --> Na2SO4 + 2H2O
According to this equation, 2 moles of NaOH are required to neutralize 1 mole of H2SO4.
The amount of NaOH in moles equals "0.125M\\times0.00650L=0.0008125mol"
Therefore, the amount in moles of H2SO4 equals "\\frac{0.0008125}{2}=0.000406mol", and the concentration is "\\frac{0.000406mol}{0.00500L}=0.0812M"
Answer: 0.0812M
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