Fe2O3 + 3H2 → 2Fe + 3H2O
M(Fe2O3) = 159.69 g/mol
n = m/M
n(Fe2O3) "= \\frac{125}{159.69}=0.783\\; mol"
n(Fe) = 2n(Fe2O3) "= 2\\times 0.783 = 1.566 \\;mol"
Answer: 1.56 mol
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