Question

A titration is carried out between HCl (aq) and 0.276 M KOH(aq). There is 38.6 mL acid, and it takes 65.3 mL of the base to reach the endpoint of the titration. What is the concentration (M) of the acid ?

Answer 1

Solution:

The reaction between hydrochloric acid (HCl) and potassium hydroxide (KOH) is:

HCl + KOH = KCl + H₂O

According to the equation: n(HCl) = n(KOH)

Therefore,

C_M(HCl) × V(HCl) = C_M(KOH) × V(KOH)

C_M(HCl) = C_M(KOH) × V(KOH) / V(HCl)

C_M(HCl) = (0.276 M × 65.3 mL) / (38.6 mL) = 0.4669 M = 0.467 M

Answer: The concentration of the acid (HCl) is 0.467 M.